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## What is the probability of getting sum 3 or 4 when 2 dice are rolled?

= **5/36**. Hope this helps!

## When 2 dice are rolled what is the probability that the sum is either 7 or 11?

What is the probability of rolling a sum of 7 or 11 with two dice? So, P(sum of 7 or 11) = **2/9**.

## What is the probability of getting a sum of either 3 or 9 when rolling two dice?

Probabilities for the two dice

Total | Number of combinations | Probability |
---|---|---|

9 | 4 |
11.11% |

10 | 3 | 8.33% |

11 | 2 | 5.56% |

12 | 1 | 2.78% |

## What is the probability of getting a sum of either 4 or 5 on a roll of two dice?

Now we can see that the sum 4 will be rolled with probability 3/36 = 1/12, and the sum 5 with probability 4/36 = **1/9**.

## What is the probability of getting a sum of 4 in a toss of a pair of dice?

There are six faces for each of two dice, giving 36 possible outcomes. If the two dice are fair, each of 36 outcomes is equally likely. Three outcomes sum to 4: (1+3), (2+2) and (3+1). Probability of getting a sum of 4 on one toss of two dice is 3/36, or **1/12**.

## What is the probability that both dice either turn up the same number?

8 Answers. The probability of rolling a specific number twice in a row is indeed **1/36**, because you have a 1/6 chance of getting that number on each of two rolls (1/6 x 1/6). The probability of rolling any number twice in a row is 1/6, because there are six ways to roll a specific number twice in a row (6 x 1/36).

## What is the sum of 2 dice?

So the average sum of dice is: E(X) = 2 ^{.} 1/36 + 3 ^{.} 2/36 + …. + 11 ^{.} 2/36 + 12 ^{.} 1/36 = 7. Question: What is the expected value of the (absolute value of the) difference of two dice?

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Random variables, distributions and expected value.

x | P(X=x) |
---|---|

2 | 1/36 |

3 | 2/36 |

4 | 3/36 |

5 | 4/36 |

## What is the probability that you obtain a sum of 7 or a sum of 11 on the first roll?

For example, since a 7 or an 11 is a winner on the first roll and their probabilities are 6/36 and 2/36, the probability of winning on the first roll is 6/36+2/36=**8/36**.

## What is the probability of getting a sum of 6?

Probability of getting a total of 6 = **5/36**.